the number N(t) of bacteria in a culture is growing exponentially. When t=0, N(t)=100, and when t=5. N(t)=300 where t is the time in hours
![the number Nt of bacteria in a culture is growing exponentially When t0 Nt100 and when t5 Nt300 where t is the time in hours class=](https://us-static.z-dn.net/files/d4d/d0f4fea733ab0d8c36dda85142e5cde3.jpg)
An exponential model can represent growth or decay
(a) The rate of the function
An exponential function is represented as:
[tex]y = ab^x[/tex]
Rewrite as:
[tex]N(t) = N(0)b^t[/tex]
From the question, we have:
So, the function becomes
[tex]N(t) = 100 \times b^t[/tex]
Substitute 5 for t
[tex]N(5) = 100 \times b^5[/tex]
This gives
[tex]300 = 100 \times b^5[/tex]
Divide both sides by 100
[tex]3 = b^5[/tex]
Take 5th root of both sides
[tex]1.25 = b[/tex]
Rewrite as:
[tex]b =1.2457[/tex]
Hence, the rate of the model is 1.2457
(b) The function
In (a), we have:
[tex]N(t) = 100 \times b^t[/tex]
Substitute 1.2457 for b
[tex]N(t) = 100 \times 1.2457^t[/tex]
(c) Time the population reaches 10000
This means that:
N(t) = 10000
So, we have:
[tex]N(t) = 100 \times 1.2457^t[/tex]
[tex]10000 = 100 \times 1.2457^t[/tex]
Divide both sides by 100
[tex]100 = 1.2457^t[/tex]
Take logarithm of both sides
[tex]log(100) = log(1.2457)^t[/tex]
This gives
[tex]log(100) = t\ log(1.2457)[/tex]
Divide both sides by log(1.2457)
[tex]t=21[/tex]
Hence, the bacteria will reach 10000 after 21 hours
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