Respuesta :

Question:-

[tex]x^2-16\ge 20 [/tex]

We need to solve the inequality.

Solution:-

[tex]\sf \longmapsto \: x^2-16\ge 20[/tex]

We need to exchange ≥ to equal ( = )sign to solve Further.

[tex]\sf \longmapsto \: x {}^{2} - 16 = 20[/tex]

Add 16 to both sides of this equation :-

[tex]\sf \longmapsto \: x^2 - 16+16=20+16[/tex]

On Simplification of this equation:-

[tex]\sf \longmapsto {x}^{2} = 20 + 16[/tex]

[tex]\sf \longmapsto {x}^{2} = 36[/tex]

Then Take the square root of 36:-

[tex]\sf \longmapsto \: x = \pm \: \sqrt{36} [/tex]

On Simplification :-

[tex]\sf \longmapsto \: x = 6 \: or \:x = - 6[/tex]

Then,

Check the interim in between two points.

So for this, Replace x = 6 to x ≥ 6 and x = -6 to x ≤ - 6.This is the solution of this question.

[tex]\sf \longmapsto \: x \le - 6[/tex]

And,

[tex]\sf \longmapsto \: x \ge \: 6[/tex]

Option D

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Henceforth,The Answer is :-

[tex]\boxed{x \: \le - 6}[/tex]

[tex]\boxed{x \ge \: 6 }[/tex]

Option D is the correct answer

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I hope this helps!

Please let me know if you have any questions.

~MisterBrian

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