Respuesta :

Answer:

[tex]\frac{11}{16}[/tex]

Step-by-step explanation:

We know

[tex]\\ \sf\longmapsto sin\Theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

Now

[tex]\\ \sf\longmapsto sinA=\dfrac{BC}{AC}[/tex]

[tex]\\ \sf\longmapsto sinA=\dfrac{11}{16}[/tex]