Question

a plane starts from rest and is accelerated 3m/s^2 over a distance of 600m what is its speed after traveling this distance? ​

Answer 1

The speed of the plane after traveling the given distance is 60 m/s.

Given the following data:

• Initial velocity = 0 m/s (since the plane starts from rest)

• Acceleration = 3 $m/s^2$

• Distance = 600 meters

To determine the speed of the plane after traveling the given distance, we would use the third equation of motion;

$V^2 = U^2 + 2aS$

Where:

• V is the final speed.

• U is the initial speed.

• a is the acceleration.

• S is the distance traveled.

Substituting the given parameters into the formula, we have:

$V^2 = 0^2 + 2(3)(600)\\\\V^2 = 3600\\\\V=\sqrt{3600}$

Speed, V = 60 m/s

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