Respuesta :
[tex]\huge \bf༆ Answer ༄[/tex]
Let's Solve ~
- [tex] \sf6x - 12 > - 6[/tex]
- [tex] \sf6x > - 6 + 12[/tex]
- [tex] \sf6x > 6[/tex]
- [tex] \sf{x} > 6 \div 6[/tex]
- [tex] \sf{x > 1}[/tex]
So, the solution belongs to ~
- [tex] \sf{x} \in(1, \infin)[/tex]
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