The stopping distance for 10 cars traveling at 55 miles per hour is shown in the table above . What is the mean (average ) stopping distance for the 10 cars ?
![The stopping distance for 10 cars traveling at 55 miles per hour is shown in the table above What is the mean average stopping distance for the 10 cars class=](https://us-static.z-dn.net/files/dc6/b80cee266969c6c306bbb56df8c9f8ed.png)
Answer:
50
Step-by-step explanation:
Add all of the numbers and divide by the number of columns. Ex.
48+49+50+51+51= 250
250÷5= 50
The average stopping distance for 10 cars is 50.2
The correct option is (D).
Average :
The average or mean is the central value of the data which can be calculated as the ratio of sum of that data to the number of that data.
The formula for average is
Average = [tex]\frac{Sum of the observations}{number of the observation}[/tex]
Here frequency of the 10 data given and therefore sum can be calculated as
1 for 48 ft. = 48
2 for 49 ft. = 2x 49 = 98
3 for 50 ft. =3 x 50 = 150
2 for 51 ft. = 2 x 51 = 102
2 for 52 ft. = 2 x 52 = 104
Therefore sum is 48 + 98 + 150 + 102 + 104 = 502
Average = [tex]\frac{502}{10}= 50.2[/tex]
The average of 10 given frequency is 50.2
The correct option is (D).
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