Mg3N2 + 6H20 – 3Mg(OH)2 + 2NH2 When 8.0 mol of Mgo N2 reacts with 50 mol of H20, what is the limiting reactant?​

Respuesta :

Answer:

Mg3N2

Explanation:

divide 50 by 6 (molar ratio) and you get something more than 8

since Mg3N2 is less it is the limiting reactant