A container holds 75 gallons of water. Water leaked out at a rate of 3 gallons every 2 days. At this rate, how many days did it take for all 75 gallons of water to leak out of the container? *plz i need help

Respuesta :

Answer:  50 days

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Explanation:

Water leaks out at a rate of 3 gallons for every 2 days. The unit rate is 3/2 = 1.5 gallons per day that's leaked out.

Let x be the number of days. After x days, the container leaks a total of 1.5x gallons of water. Set this equal to 75 and solve for x. We'll divide both sides by 1.5

1.5x = 75

x = 75/(1.5)

x = 50

It takes 50 days for the container to empty.

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Here's another way to solve:

(3 gallons leaked)/(2 days) = (75 gallons leaked)/(x days)

3/2 = 75/x

3x = 2*75 .... cross multiply

3x = 150

x = 150/3

x = 50 days

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Yet another way to solve:

3 gallons : 2 days

25*(3 gallons) : 25*(2 days) ..... multiply both parts by 25

75 gallons : 50 days

We multiplied by 25 to get that "3 gallons" to "75 gallons". You can use trial and error, or note that 75/3 = 25.

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