Question:-
[tex]7 x + 13 + 2 ( 5 x − 3 ) > 7[/tex]
We need to solve this inequality.
Solution:-
[tex]\sf \longmapsto7 x + 13 + 2 ( 5 x − 3 ) > 7[/tex]
Firstly, simplify the two sides of the inequality :-
On Simplification:-
[tex]\sf \longmapsto \: 17x+7>7[/tex]
This is our new equation.
Then, Subtract 7 from both sides :-
[tex]\sf \longmapsto17x+7 - 7>7 - 7[/tex]
On Simplification:-
As (-) and (+) = (-),It will be 7-7.
[tex]\sf \longmapsto17x + 0 > 0[/tex]
[tex]\sf \longmapsto \: 17x > 0[/tex]
Divide the two sides by 17:-
[tex]\sf \longmapsto \: \dfrac{17x}{17} > \dfrac{0}{17} [/tex]
On Simplification:-
Cancel 17 and 17, leave x.If the numerator or denominator is 0, then the solution of that Fraction is 0.
[tex]\sf \longmapsto \dfrac{ \cancel{17}x}{ \cancel{17}} > \dfrac{0}{17} [/tex]
[tex]\sf \longmapsto \: x > 0[/tex]
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Henceforth the answer of the inequality is :-
[tex]\huge{\boxed{\boxed{\bf x > 0}}}[/tex]
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I hope this helps!
Please let me know if you have any questions.
~MisterBrian