Find m∠NAB
a) 55
b) 110
c) 80
d) 95
![Find mNAB a 55 b 110 c 80 d 95 class=](https://us-static.z-dn.net/files/d52/03050d90ac76322abeb6a513b50db793.jpg)
Answer:
95
Step-by-step explanation:
The exterior angle is the sum of the opposite interior angles
8x+7 = 5x+40
Subtract 5x from each side
8x+7-5x = 5x+40-5x
3x+7 = 40
Subtract 7 from each side
3x+7-7 = 40-7
3x=33
Divide by 3
3x/3 = 33/3
x = 11
Find <NAB
<NAB = 8x+7 = 8*11+7 = 88+7 = 95
Answer:
[tex]\huge\boxed{\sf <NAB = 95\°}[/tex]
Step-by-step explanation:
Key: The measure of exterior angle is equal to the sum of measures of non-adjacent interior angles.
So, we get:
8x + 7 = 5x + 40
Subtract 5x and 7 to both sides
8x - 5x = 40 - 7
3x = 33
Divide both sides by 3
x = 11
Now,
∠NAB = 8x + 7
∠NAB = 8(11) + 7 [x = 11]
∠NAB = 88 + 7
∠NAB = 95°
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!