Question

If a ball experiencing no air resistance is dropped from a plane flying at 500.0 m above the ground and the ball lands 400.0
m horizontally from the initial dropping point, how fast was the plane flying when the ball was released. (Assume no air
resistance​

Answer 1

Answer:

Explanation:

time to drop 500 m

h = ½gt²

t = √(2h/g)

t = √(2(500)/9.8) = 10.1 s

v = d/t = 400.0/10.1 = 39.6 m/s   (about 143 kph)