Question

A 1.3kg box of frozen chocolate waffles is pulled at condtant velocity across a table by a rope. The rope is at angle of 60 degrees and under a tension of 4N.
What is the coefficient of friction between the table and the box

Answer 1

Answer:

Explanation:

ΣF = ma

Fcosθ - μ(mg - Fsinθ) = ma

constant velocity means a = 0

Fcosθ - μ(mg - Fsinθ) = 0

μ(mg - Fsinθ) = Fcosθ

μ = Fcosθ / (mg - Fsinθ)

μ = 4cos60 / (1.3(9.8) - 4sin60)

μ = 0.2156125...

μ = 0.22