Question

What is the area of a triangle whose vertices are R(-4, 2). S(1, 2), and T(-5, - 4) ?
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units2

Answer 1

Answer:

-15 sq. units

Step-by-step explanation:

To solve this, we'll use the formula.

Coordinate Geometry formula for a triangle:

$\frac{1}{2} [(x_1 (y_2 - y_3) + x_2 (y_3 - y_1) + x_3(y_1 - y_2)]$

R(−4, 2), S(1, 2), and T(−5, −4) as the vertices of △RST

$x_1 = - 4, y_1 = 2$

$x_2 = 1, y_2 = 2$

$x_3 = - 5, y_3 = - 4$

Plugin the values; solve

$\frac{1}{2} [-4 (2 - (-4)) + 1 (- 4 - 2) + (-5) (2 - 2)]$

$=\frac{1}{2} [-24 - 6 - 0]$

$= \frac{1}{2} [-30]$

$= \frac{-30}{2}$

$= -15$

Therefore, the area of the triangle is -15 sq. units.