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Answer:

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Step-by-step explanation:

2-A1  (20-25 Min.)

1.  The cost driver for both resources is number of times the plant is cleaned. Labor cost is a fixed-cost resource, and cleaning supplies is a variable cost.  Costs for cleaning between 4 and 8 times a month are:

Number of

times plant Square Feet  Cleaning Supplies  Cost per

is cleaned Cleaned Labor Cost Cost**  Total cost  Cleaning

4 200,000* $21,000  $ 8,000***  $29,000   $7,250

5 250,000   21,000 10,000  31,000   $6,200

6 300,000   21,000 12,000  33,000   $5,500

7 350,000   21,000 14,000  35,000  $5,000

8 400,000   21,000 16,000  37,000  $4,625

* 4 × 50,000 square feet

** Cleaning supplies cost per time the plant is cleaned = $8,000 ÷ 4 = $2,000

*** $2,000 per cleaning × number of times plant is cleaned

The predicted total cost to clean the plant during the next quarter is the sum of the total costs for monthly cleanings of 5, 6, and 8 times. This is

  $31,000 + $33,000 + $37,000 = $101,000

2.  If Napco hires the outside cleaning company, all its cleaning costs will be variable at a rate of $5,700 per cleaning. The cost driver will be “number of times cleaned.” The predicted cost to clean a total of 5 + 6 + 8 = 19 times is 19 × $5,700 = $108,300. Thus, Napco will save by not hiring the outside cleaning company.

The table below shows the total costs for the two alternatives. If Napco expects average “times cleaned” to be 6 or more, it would save by cleaning with its own employees.  If Napco expects to average 5 or fewer cleanings per month, it would save by outsourcing.

Napco Cleans Plant

Outsource Cleaning Plant

Times Cleaned

Napco

Times Cleaned

Outside

4

$ 29,000

4

$22,800

5

  31,000

5

 28,500

6

  33,000

6

 34,200

7

  35,000

7

 39,900

8

  37,000

8

 45,600

Answer: n = 2(2C-3)/5

Step-by-step explanation:

[tex]\begin{array}{l}C=1.5+1.25n\\\\100\ \cdot\ \left(1.5+1.25n=C\right)\ \cdot100\\\\150+125n=C\cdot100\\\\150+125n-150=C\cdot100-150\\\\125n=C\cdot100-150\\\\\frac{125n}{125}=\frac{C\cdot100}{125}-\frac{150}{125}\\\\n=\frac{100C-150}{125}\\\\n=\frac{50\left(2C-3\right)}{125}\\\\n=\frac{2\left(2C-3\right)}{5}\end{array}[/tex]

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