Question

What volume does 0.067 moles of He gas occupy at STP?

Answer 1

The volume of 0.067 moles of helium (He) gas at STP is equal to 1.5017 Liters.

Given the following data:

• Number of moles = 0.067 moles

Scientific data:

• Standard pressure = 1 atm.

• Standard temperature = 273 K

• Ideal gas constant, R = 0.0821 L⋅atm/mol⋅K

To determine the volume of 0.067 moles of helium (He) gas at STP, we would use the ideal gas equation:

$V = n\frac{RT}{P}$

Where;

• P is the pressure.

• V is the volume.

• n is the number of moles of substance.

• R is the ideal gas constant.

• T is the temperature.

Substituting the given parameters into the formula, we have;

$V = \frac{0.067 \times 0.0821 \times 273}{1}$

Volume, V = 1.5017 Liters

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