Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

y=-16x^2+248x+116

Answer 1

Answer:

Step-by-step explanation:

The rocket will hit the ground when y = 0. If you use the quadratic equation:

x = (-248±√(2482-4(-16)(116))/(2(-16))