Question

A submarine is cruising at an elevation of
-250/3 meters below sea level, then
descends another 120% meters into the
sea. What is the new location of the
submarine?……NO LINKS

Answer 1

Answer:

Step-by-step explanation:

these are two different questions .

first i solve first

position of submarine= -250/3 meters below see level

height descended=120 % of 250/3=120/100 ×(250/3)=300,00/300=100 m

new location=-250/3+(-100)=-650/3 below see level.

2nd question

position of submarine=-250 2/3=-752/3 m below see level

height descended=120 5/8=965/8 m =-965/8 m below see level

new positin=-752/3+(-965/8)=-(6016+2895)/24=-8911/24=-371 7/24m below sesa level.