Given the triangle below and the equation: sin A = 3/5.
Determine the value of b.

Using the trigonometry ratio and Pythagorean Theorem, the value of b in the triangle is: 4.
Recall:
Given the trigonometry ratio of sin A = 3/5
Recall that, sin ∅ = opp/hyp (SOH)
Thus, this means that, in sin A = 3/5,
Thus, find the value of b by applying the Pythagorean theorem.
[tex]b = \sqrt{c^2 - a^2}[/tex] (Pythagorean Theorem)
[tex]b = \sqrt{5^2 - 3^2}\\\\\mathbf{b = 4}[/tex]
Therefore, using the trigonometry ratio and Pythagorean Theorem, the value of b in the triangle is: 4.
Learn more about Trigonometry ratios on:
https://brainly.com/question/4326804