Respuesta :

The number of moles of gas B present in the gas mixture is 2.72 moles.

The given parameters;

  • Volume of the gases, V = 14 L
  • Temperature of the gases, T = 323 K
  • Total pressure of the gases, P = 8 atm
  • Number of moles of gas A = 1.5 moles

The total number of moles of the gases is calculated by applying ideal gas law;

PV = nRT

where;

R is ideal gas constant = 0.0821 L.atm./mol.K

n is the total mole of the gases

[tex]n =\frac{PV}{RT} \\\\n = \frac{8 \times 14}{0.0821 \times 323} \\\\n = 4.22 \ moles[/tex]

The number of moles of gas B is calculated as follows;

[tex]n_B = 4.22 - n_A\\\\n_B = 4.22 - 1.5\\\\n_B = 2.72 \ moles[/tex]

Learn more about ideal gas law here: https://brainly.com/question/21912477

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