A mass m is released from a height h above the ground. It is given an initial horizontal velocity of magnitude v0. What is the speed of the mass when it hits the ground

Respuesta :

The speed of the mass when it hits the ground from the given height is [tex]\sqrt{2gh}[/tex].

The given parameters:

  • mass of the object, = m
  • height of fall = h
  • initial horizontal velocity, = V₀

The final velocity of the ball when it hits the ground is calculated as follows;

[tex]v_f^2 = v_0_y^2 + 2gh\\\\[/tex]

where;

  • [tex]v_0_y[/tex] is the initial vertical velocity velocity = 0
  • g is the acceleration due to gravity = 9.8 m/s²

[tex]v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh}[/tex]

Thus, the speed of the mass when it hits the ground from the given height is [tex]\sqrt{2gh}[/tex].

Learn more about final velocity here: https://brainly.com/question/17956487

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