The speed of the mass when it hits the ground from the given height is [tex]\sqrt{2gh}[/tex].
The given parameters:
- mass of the object, = m
- height of fall = h
- initial horizontal velocity, = V₀
The final velocity of the ball when it hits the ground is calculated as follows;
[tex]v_f^2 = v_0_y^2 + 2gh\\\\[/tex]
where;
- [tex]v_0_y[/tex] is the initial vertical velocity velocity = 0
- g is the acceleration due to gravity = 9.8 m/s²
[tex]v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh}[/tex]
Thus, the speed of the mass when it hits the ground from the given height is [tex]\sqrt{2gh}[/tex].
Learn more about final velocity here: https://brainly.com/question/17956487
