Question

Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2

Answer 1

The magnitude of the acceleration of the box is 2 m/s².

The given parameters;

• mass of the box, m = 50 kg
• first force, F₁ = 60 N south
• second force, F₂ = 80 east

The resultant of the two given forces is calculated as follows;

$F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N$

The magnitude of the acceleration of the box is calculated as follows;

$F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2$

Thus, the magnitude of the acceleration of the box is 2 m/s².

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