The number of moles of XeF4 that can be created would be 0.5 moles.
From the equation of the reactiobn:
Xe (g) 2 F₂ (g) ---> XeF₄ (g)
The mole ratio of Xe to F2 is 1:2. Hence, in the presence of 1 mole Xe and 1 mole F2, F2 would be limiting the reaction.
This means that the amount of F2 would determine the amount of XeF4 that would be produced from the reaction.
The mole ratio of F2 to XeF4 according to the equation is 2:1. This means that for every 1 mole of F2 introduced into the reaction, 0.5 moles of XeF4 will be produced.
In this case, 1 mole of F2 is introduced. Thus, the mole of XeF4 that would be produced would be:
1/2 = 0.5 moles.
More on stoichiometric calculations can be found here: https://brainly.com/question/8062886?referrer=searchResults
