The maximum value of the objective function is 3080
The vertices of a feasible region are given as
(14, 2), (0, 9), (6, 8), (10, 3)
The objective function is given as:
[tex]\mathbf{P = 180x + 250y}[/tex]
Substitute the ordered pairs in the objective function
Point (14,2)
[tex]\mathbf{P = 180 \times 14 + 250 \times 2}[/tex]
[tex]\mathbf{P = 3020}[/tex]
Point (0,9)
[tex]\mathbf{P = 180 \times 0 + 250 \times 9}[/tex]
[tex]\mathbf{P = 2250}[/tex]
Point (6,8)
[tex]\mathbf{P = 180 \times 6 + 250 \times 8}[/tex]
[tex]\mathbf{P = 3080}[/tex]
Lastly, we have point (10,3)
[tex]\mathbf{P = 180 \times 10 + 250 \times 3}[/tex]
[tex]\mathbf{P = 2550}[/tex]
The maximum value of P is calculated to be 3080.
Hence, the maximum value of the objective function is 3080
Read more about objective functions at:
https://brainly.com/question/11206462
