Question

Triangle PQR has coordinates P (0, 0), Q (-4, 0), and R (0, 2). If ΔPQR ≅ ΔXYZ, what is the measure of XY?
A) 1 units
B) 2 units
C) 3 units
D) 4 units

Answer 1

Given that ΔPQR and ΔXYZ are congruent triangles, the measure of XY is: D) 4 units

Recall:

• Congruent triangles have pairs of congruent angles and congruent sides.

• Distance between two vertices can be calculated using the distance formula: $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Given ΔPQR ≅ ΔXYZ, therefore, PQ = XY.

Find the distance between P(0, 0) and Q(-4, 0) using$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$PQ = \sqrt{(-4 - 0)^2 + (0 - 0)^2}\\\\\mathbf{PQ = 4 units}$

• Since ΔPQR ≅ ΔXYZ, therefore the measure of XY is: D) 4 units

Learn roe about congruent triangles on:

https://brainly.com/question/2938476

Answer 2

Answer:

4 units

Step-by-step explanation: