Question

The Ninoy Aquino International Airport (NAIA) and Singapore Changi Airport (SIN) are about 2,400 kilometers apart. A Singapore Airlines passenger plane leaves NAIA, traveling towards SIN at an average speed of 800 kilometers per hour. A Philippine Airline passenger plane leaves SIN at the same time, traveling toward NAIA, averaging 640 kilometers per hour. How long will it take them to meet?

Answer 1

The relative velocity of one plane with respect to the other plane is given

by the sum of the velocity of the two planes.

• The time it would take the two planes to meet is  $\underline{1. \overline 6 \ km/hr}$

Reasons:

The distance between the two airports = 2,400 km

Speed of the plane from NAIA = 800 kilometer per hour

Speed of the plane coming from SIN = 640 kilometers per hour

Let t represent the time after which the two planes meet, we have;

800 × t + 640 × t = 2,400

$\displaystyle t = \frac{2,400 \ km}{800 \ km/hr + 640 \ km/hr} = \frac{5}{3} \ km/hr = 1.\overline 6 \ km/hr$

The time after which the two planes meet, t = $\underline{1. \overline 6 \ km/hr}$

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