Question

Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.

A pair of kids and a pair of adults decided to compete in a three-legged race. The kids got to start 15 yards ahead of the adults, since they had shorter legs. When they were told to start, the kids hobbled forward at a rate of 1 yard per second, and the adults hobbled after them at a rate of 4 yards per second. Soon they were side-by-side. How long did that take? How far did the adults go?


It took seconds for the adults to go yards and catch up to the kids?

Answer 1

A system of equations is simply a system that contains related equations of multiply variables

It took 5 seconds for the adults to go 20 yards and catch up to the kids

Let x represents the time of the race

The kids started 15 yards ahead, and they raced at 1 yard per second.

So, the kids' equation is represented as: $\mathbf{k =15 + x}$

The adults' raced at 4 yards per second.

So, the adults' equation is represented as: $\mathbf{a =4x }$

When they are side by side, we have the following equivalent equation

$\mathbf{4x = 15 + x}$

Subtract x from both sides

$\mathbf{3x = 15}$

Divide both sides by 3

$\mathbf{x = 5}$

It means that, it took the adults 5 seconds to catch up with the kids

Substitute 5 for x in any of the equations to calculate the distance travelled.

$\mathbf{a =4 \times 5}$

$\mathbf{a =20}$

It means that, the adults catch up with the kids at 20 yards

Read more about systems of equations at:

https://brainly.com/question/12895249

Answer 2

Answer:

The adults went 123 yards and caught up to the kids in 41 seconds

Step-by-step explanation:

ixl :)