Question

10. What do you have to do to the coefficients of equation I below to get to equation II?
i. 2 SnO2 + 4 H2  2 Sn + 4 H2O
ii. SnO2 + 2 H2  Sn + 2 H2O

a) Both equation I and II are balanced, but equation I is the correct way to write the balanced equation.

b) Can you divide equation II by another factor and still have it be correct? Why or why not?


c) In a complete sentence, write down a method you could use to determine if an equation is written in the correct way.

Answer 1

1.  We have to divide the coefficient of equation I by 2 to get equation II.

a. Both equations are balanced but equation II is the correct way to write a

balance equation.

b. It will be correct if we divide equation II coefficient by another factor

but  we will get fractions as coefficient. For example

$\frac{1}{2}$SnO₂ + H₂→  $\frac{1}{2}$Sn + H₂O

c. The correct method is checking if the number of moles of element on

the reactant side is same as the those on the product side. And the

conventional way is making sure the coefficients are whole numbers.

i.   2SnO₂ + 4H₂ → 2 Sn + 4H₂O

ii.  SnO₂ + 2H₂→  Sn + 2H₂O

We have to divide the coefficient of equation I by 2 to get equation II.

Both equations are balanced but equation II is the correct way to write a

balance equation.

If we divide the coefficients of equation II by another number, we will not

get a whole number coefficients. The coefficient will be fractions , it will

be  correct but its not conventional.  

The best method to know if equation is written the correct way is checking

if the coefficient are in the lowest whole number factors.

we also have to check if each moles of elements found in the reactant is

the same in the product side.

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Answer 2

Answer:We have to divide the coefficient of equation I by 2 to get equation II.

Explanation: