[tex]csc(\theta )=-5\qquad -\frac{\pi }{2}<\theta <\frac{\pi }{2} \\\\[-0.35em] ~\dotfill\\\\ csc(\theta )=-5\implies \stackrel{\textit{using the reciprocal of } csc(\theta )}{\cfrac{1}{sin(\theta )}=-5}\implies \cfrac{1}{-5}=sin(\theta ) \\\\\\ sin^{-1}\left( -\frac{1}{5} \right) = sin^{-1}[sin(\theta )]\implies sin^{-1}\left( -\frac{1}{5} \right) = \theta \implies \begin{array}{llll} -11.54^o\\ ~\hfill or\\ 348.46^o \end{array} \approx \theta[/tex]