Question

what is the equation of the line that is perpendicular to y=-1/4x-2 and goes through the point (-2,-3)

Answer 1

Step-by-step explanation:

y=-1/4x-2

1/4x+y+2=0.........1

line perpendicular to eqn 1 is

x-1/4y+k=0

as the line passes through the (-2,-3)

-2-1/4×-3+k=0

-1+4k=0

K=1/4

the eqn is 4x-y+1=0