[tex] \: [/tex]
step-by-step explanation
[tex]y = x +2[/tex]
[tex]y = 1x + 1[/tex]
since the equation is written in slope-intercept form y=mxb, identify the slope of the line as the coefficient next to the variable x
[tex]y = 1x + 1 \: ,m = 1[/tex]
[tex]y = 1x + 1 \: ,m = 1 \: ,b = 1[/tex]
so the answer to the equation is
[tex] = m = 1,b = 1[/tex]
[tex] \: [/tex]
#1
[tex]\\ \sf\longmapsto y=x+2[/tex]
Slope intercept form=y=mx+b
On comapring we get
#2
[tex]\\ \sf\longmapsto y+3=\dfrac{-1}{4}x[/tex]
[tex]\\ \sf\longmapsto y=-\dfrac{1}{4}x-3[/tex]