Question

how do you do this?? could you kindly include your work pls..

Answer 1

Answer:

B.  0.

Step-by-step explanation:

(x + 2y)dy/dx = 2x - y

dy/dx = (2x -y)/(x + 2y)

Using implicit differentiation and the Quotient Rule:

d^2y/dx^2 =  (x + 2y)(2 - y*dy/dx) - ((2x - y)(1 + 2y*dy/dx)) / (x + 2y)^2

At the point (3, 0), dy/dx = (6-0)/(3 + 2(0)) = 2.

So substituting in d^2y/dx^2, we have:

(3 + 0)(2 - 0) - (6-0)(1 + 2(0))/  (3+0)^2

= (6 -  6) / 9

= 0.