Question

At a particular time, a tree casts a shadow 17 m long on horizontal ground. At the same time, a vertical pole 3 m high casts a shadow 4 m long. Calculate the height of the tree to the nearest tenth of a meter.

Answer 1

Using a system of equations, the height of the tree would be 12.80 meters.

Equating the height and shadows of the tree and pole :

Height of pole / shadow of pole = height of tree / shadow of tree

Representing the equation thus :

Let the height of the tree = h

3/4 = h/17

Cross multiply

4h = 17 × 3

4h = 51

Divide both sides by 4

h = 51/4

h = 12.75.

Hence, the height of the tree to the nearest tenth of a meter is 12.80 meters.

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