Question

If point A is located at (-7 , 5) on a coordinate plane, and point B is located at (4 , 5), what is the distance between the two points?​

Answer 1

Answer:

$11$

Step-by-step explanation:

$\sf{Use\: the\: distance\: formula\: to\: determine\: the\: distance\: between\: two\: points.$

$\sf{Distance=\sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

$\mathrm{Plug\:the\:points}$

$\sqrt{\left(4-\left(-7\right)\right)^2+\left(5-5\right)^2}$

$(4+7)^2=11^2\\(5-5)^2=0$

$\sqrt{11^2+0}$

$11^2+0=11^2\\\sqrt{11^2}$

$\mathrm{Apply\:radical\:rule:\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\:\mathrm{is\ greater\ than \:or\ equal\: to \:0}$

$=11$