The probability that Ethan does NOT have computer science homework is 0.3
From the information given:
However, in probability, the sum of all event outcomes is always equal to 1.
∴
[tex]\mathbf{P(A) + P(A^c) = 1}[/tex]
where;
Thus;
[tex]\mathbf{ P(A^c) = 1- P(A)}[/tex]
[tex]\mathbf{ P(A^c) = 1- \dfrac{7}{10}}[/tex]
[tex]\mathbf{ P(A^c) =\dfrac{10 -7}{10}}[/tex]
[tex]\mathbf{ P(A^c) =\dfrac{3}{10}}[/tex]
[tex]\mathbf{ P(A^c) =0.3}[/tex]
Therefore, we can conclude that the probability that Ethan does NOT have computer science homework is 0.3
Learn more about probability here:
https://brainly.com/question/11234923?referrer=searchResults