Jacky has 26.88 minutes before the appointed time
Let the distance between Jacky and her friends be x
Let the normal time expected for Jacky to reach her friend's location be t
Time = Distance / Speed
if she bikes at a speed of 10 mph he will be 3 minutes late for the meeting
Time of lateness in hours = 3/60 = 0.05 hours
t + 0.05 = x/10
10t + 0.5 = x..........(1)
If she bikes at a speed of 12 mph, she will be there 2 minutes before the agreed meeting time
2 minutes = 0.033 hours
t - 0.033 = x/12
12t - 0.396 = x.......(2)
Compare equations (1) and (2)
10t + 0.5 = 12t - 0.396
12t - 10t = 0.5 + 0.396
2t = 0.896
t = 0.896/2
t = 0.448 hours
t = 0.448 x 60
t = 28.88 minutes
Jacky has 26.88 minutes before the appointed time
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