Question

A local high school has both male and female students.
Each student either plays a sport or doesn't.
The two-way table summarizes a random sample of 70 students.
Female
Male
No sport
10
7
Sport 32 21
Let no sport be the event that a randomly chosen student (from the table) does not play a sport.
Let male be the event that a randomly chosen student (from the table) is male.
Find the following probabilities. Write your answers as decimals.
(a) P(male) = 0
(6) P(no sport and male) = 0
(c) P(no sport male) = 0

Answer 1

Answer:

a. P(male) = 0.4

b. P(no sport and male) = 0.1

c. Unclear question (isn't it the same as b.?)

Step-by-step explanation:

The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;

$\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]$

a.

$P(male) = \frac{7 + 21}{70} \\\\ = \frac{28}{70} \\\\ = \frac{2}{5}$

b.

Using the tree diagram in the picture;

$P(no \ sport \ and \ male) = \frac{2}{5} * \frac{1}{4} \\\\ = \frac{1}{10}$