Answer:
[tex]\huge\boxed{\sf t = 40\ seconds}[/tex]
Explanation:
Given data:
Acceleration = a = 0.5 m/s²
Initial Velocity = Vi = 0 m/s
Distance = S = 400 m
Required:
Time = t = ?
Formulas used:
2 formulas
Solution:
Using third equation of motion firstly
2as = Vf²-Vi²
2(0.5)(400) = Vf² - 0²
400 = Vf²
Taking sqrt
Vf = 20 m/s
Now, Using First equation of motion:
Vf = Vi + at
20 = 0 + 0.5t
0.5 t = 20
Divide both sides by 0.5
t = 40 seconds
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!