Question

Which substance is the limiting reactant when 24.0 g of sodium hydroxide reacts with 18.0 g of oxygen and 12.0 g of sulfur according to the following chemical equation:
2 S(s) + 3 O2(g) + 4 NaOH(aq) → 2 Na2SO4(aq) + 2 H2O(l)

Answer 1

Answer:

Sodium hydroxide.

Explanation:

Don't be confused by the fact that you have three reactants, you can find the limiting reagent by using the same technique you use for reactions that have two reactants.

for more info... use the link

https://socratic.org/questions/which-substance-is-the-limiting-reactant-when-2-0-g-of-sulfur-reacts-with-3-0-g-#171384

hope it helps and please give brainliest

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