Respuesta :
Answer:
18
At STP, 22.4 liters of a gas forms one mole that is 6.023×10
23
molecules.
Volume of CO
2
in 1 litre of air =
100
0.03
×1 L
∴ No. of molecules of CO
2
=
22.4
6.023×10
23
×
100
0.03
=8.066×10
18
Explanation:
I guess it's this
- R=8.314J/molK
- P=772mmHg
- T=0°C=273K
- V=20L
[tex]\\ \sf\longmapsto PV=nRT[/tex]
[tex]\\ \sf\longmapsto n=\dfrac{PV}{RT}[/tex]
[tex]\\ \sf\longmapsto n=\dfrac{772(20)}{8.314(273)}[/tex]
[tex]\\ \sf\longmapsto n=\dfrac{15440}{2269.722}[/tex]
[tex]\\ \sf\longmapsto n=6.8mol[/tex]