Question

please help to find an explicit formula for calculating the sum Mn

Answer 1

The explicit formula for calculating the sum is

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

The sum of the nth term of a sequence is expressed as;

$S_n=\frac{n}{2}(2a+(n-1)d)$

a is the first term

d is the common difference

n is the number of terms

For the sequence  0 + 1 + 2 + 3  +...

$S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}$

Similarly for the sequence:

1 + 2+ 3 + 4+...

$S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}$

Taking the product of the sum to get the explicit formula for calculating the sum

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

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