Respuesta :
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The work done in the given case is 0
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
For calculating the work done by an object we apply the formula, that is ~
- [tex]f \times s \times \cos( \theta) [/tex]
where f represents force applied, and s represents displacement.
but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get
- [tex]f = 0 \times s \times \cos( \theta) [/tex]
hence,
- [tex]work \: done = 0[/tex]
Solution:
- Here, though the man is applying force on the wall, the work done is zero.
- This is because work is said to be done only when a force acting on a body produces motion in it in the direction of the force applied.
- Here, the man is trying to push the wall with a great force. He might fell exhausted after some time and say that he has done a lot of work.
- But in terms of physics, he has done no work because the force applied by the person has not produced any displacement. We know, work done = force × displacement. If displacement is zero, then work done is zero.
So therefore, we can conclude that the man hasn't done any work.
Hope it helps.
Do comment if you have any query.