Question

what is the perimeter, in grid units, of a regular octagon that has one side with endpoints (-4, -3) and (-4, 8)

Answer 1

Answer:

88

Step-by-step explanation:

Let's find the length of one side. The perimeter will be 8 times that since it's a regular octagon.

$d= \sqrt{(-4+(-4))^2+(8-(-3))^2} = \sqrt{0^2+(11)^2}= 11$

Perimeter has to be $8\times 11 = 88$