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What is the osmotic pressure of a solution made by dissolving 35.0 g of glucose, C6H12O6, in enough water to form 800.0 mL of solution at 11.0 ∘C ?

Respuesta :

neiljohncabaltera

Answer:

Osmotic pressure, a colligative property can be determined from

π = iMRT

π = osmotic pressure in atm

i = van't Hoff factor = 1 for glucose, a non electrolyte

M = molarity = 30.0 g x 1 mol/180 g x 1/0.650 L = 0.2564 M

R = gas constant = 0.0821 Latm/Kmol

T = temperature Kelvin = 14.0º + 273 = 287K

Explanation:

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