The weight of the three brothers, Xavier, Yosef and Zeke are 35 lbs, 65 lbs and 100 lbs respectively.
Given:
Total weight = 200 pounds
Xavier weight = x
Yosef weight = y
Zeke weight = z
Xavier and Yosef together are equal to Zeke.
x + y = z (1)
Yosef is 5 less than twice Xavier
y = 2x - 5 (2)
substitute y = 2x - 5 into (1)
x + y = z (1)
x + (2x - 5) = z
x + 2x - 5 = z
3x - 5 = z
Recall
x + y + z = 200
x + (2x - 5) + (3x - 5) = 200
x + 2x - 5 + 3x - 5 = 200
6x - 10 = 200
6x = 200 + 10
6x = 210
x = 210/6
x = 35 lbs
Therefore,
y = 2x - 5
= 2(35) - 5
= 70 - 5
y = 65 lbs
and
3x - 5 = z
3(35) - 5 = z
105 - 5 = z
100 lbs = z
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