Question

An aqueous solution known as Ringer's lactate is administered intravenously to trauma victims suffering from blood loss or severe burns. The solution
contains the chloride salts of sodium, potassium, and calcium and is also 4.75 mM in sodium lactate (NaC3H5O3).
How many grams of sodium lactate are needed to prepare 8.50 liters of Ringer's lactate?

Answer 1

The mass of  sodium lactate required to prepare 8.50 liters of Ringer's lactate is 4.5 g.

From the question, we are told that the solution contains 4.75 mM in sodium lactate (NaC3H5O3). This solution is administered intravenously to trauma victims suffering from blood loss or severe burns.

But we know that;

Number of moles = concentration × volume

And;

Number of moles = mass/molar mass

mass/molar mass =  concentration × volume

Concentration = 4.75 × 10^-3 M

Volume =  8.50 liters

Molar mass of NaC3H5O3 = 112.06 g/mol

Mass =  concentration × volume  × molar mass

Mass =  4.75 × 10^-3 M ×  8.50 liters × 112.06 g/mol

Mass = 4.5 g

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