Use the fact that -1 ≤ sin(x) ≤ 1.
Then
20 ≥ -20 sin(x) ≥ -20 … … … (multiply each side by -20)
-20 ≤ -20 sin(x) ≤ 20 … … … (swap the endpoints)
10x - 20 ≤ 10x - 20 sin(x) ≤ 10x + 20 … … … (add 10x to each side)
and over the interval [7, 8], we have
7 ≤ x ≤ 8
70 ≤ 10x ≤ 80 … … … (multiply each side by 10)
so that the whole integrand is bounded by
70 - 20 ≤ 10x - 20 sin(x) ≤ 80 + 20
50 ≤ 10x - 20 sin(x) ≤ 100
Take m = 50 and M = 100. It follows that
[tex]50(8-7) \le \displaystyle \int_7^8 (10x-20\sin(x)) \, dx \le 100(8-7)[/tex]
which places the value of the integral between 50 and 100.