Question

If a student finds the weight of the sodium chloride to be 28.5g
Calculate the number of particles.
( Na=23, C1= 35.5)

Answer 1

The number of particles in 28.5 g of sodium chloride, NaCl is 2.93×10²³ particles

From Avogadro's hypothesis,

1 mole of NaCl = 6.02×10²³ particles

But,

1 mole of NaCl = 23 + 35.5 = 58.5 g

Thus, we can say that:

58.5 g of NaCl = 6.02×10²³ particles

• With the above information, can obtain their number of particles in 28.5 g of NaCl. This can be obtained as illustrated below:

58.5 g of NaCl = 6.02×10²³ particles

Therefore,

28.5 g of NaCl =

$\frac{28.5 \times 6.02 \times {10}^{23} }{58.5}$

28.5 g of NaCl = 2.93×10²³ particles

Thus, the number of particles in 28.5 g of sodium chloride, NaCl is 2.93×10²³ particles

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