Using a confidence level of 95%, the margin of error for the estimate of the mean number of television hours watched will be 1.129
The approximate margin of error can be calculated using the relation :
- Margin of Error = [tex] Z_{\frac{α}{2}} \frac{σ}{\sqrt{n}} [/tex]
- Sample size, n = 25
- Standard deviation, = 2.88
- Confidence level = 95%
- [tex] Z_{\frac{α}{2}} = 1.96 [/tex]
Margin of Error = [tex] 1.96 \frac{2.88}{\sqrt{25}} [/tex]
Margin of Error = [tex] 1.96 \frac{2.88}{5} [/tex]
Margin of Error = [tex] 1.96 \times 0.576 [/tex]
Margin of Error = [tex] 1.129 [/tex]
Therefore, the margin of error for the estimate of the mean number of television hours watched is 1.129.
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