Provided That :-
[tex]\qquad[/tex] According to the question :-
[tex]\qquad \pmb{\sf\longrightarrow X+5 = 3(x-9)}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow X+5= 3x- 27}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow X-3x = -27-5}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow -2x= -32}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow 2x= 32}[/tex]
[tex]\qquad \pmb{\sf\longrightarrow X= \cancel{\dfrac{32}{2}}= 16}[/tex]
[tex]\qquad \longrightarrow {\pink{\underline{\underline{\pmb{\sf{ X = 16 }}}}}}[/tex]
Therefore–
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