Respuesta :
Answer:
A snowmobile is used to pull two sleds across the ice. The mass of the snowmobile and the rider is 320 kg. The mass of the first sled behind the snowmobile is 120 kg and the mass of the second sled is 140 kg. The ground exerts a force of 1500 N [forward] on the snowmobile. The coefficient of kinetic friction for the sleds on ice is 0.15. Assume that no other frictional forces act on the snowmobile. Calculate the acceleration of the snowmobile and the sleds.
Explanation:
A snowmobile is used to pull two sleds across the ice. The mass of the snowmobile and the rider is 320 kg. The mass of the first sled behind the snowmobile is 120 kg and the mass of the second sled is 140 kg. The ground exerts a force of 1500 N [forward] on the snowmobile. The coefficient of kinetic friction for the sleds on ice is 0.15. Assume that no other frictional forces act on the snowmobile. Calculate the acceleration of the snowmobile and the sleds.
The acceleration of the snowmobile and the sleds is 1.08ms⁻².
What is acceleration?
Acceleration exists as the rate of change of velocity. Usually, acceleration indicates the speed exists changing, but not always. When an object moves in a circular path at a constant speed, it stands still accelerating, because the direction of its velocity exists altering.
Given:
Mass of the snowmobile and the rider= 320 kg
Mass of the first sled= 120kg
Mass of the second sled= 140kg
Forward force by ground= 1500N
The coefficient of kinetic friction= 0.15
To find:
The acceleration of the snowmobile and the sleds
Solution:
Considering the whole snowmobile and sleds in a single system, the equation for acceleration is:
Forward force - frictional force= (320+120+140) a
Frictional force= Normal reaction on the system X coefficient of kinetic friction
= (320+120+140)g X 0.15
= 870N
Substituting the value in the equation,
1500 - 870 = 580 a
or a = 1.08ms⁻²
Hence, The acceleration of the snowmobile and the sleds is 1.08ms⁻².
To learn more about acceleration of the snowmobile refer to:
https://brainly.com/question/13967887
#SPJ2
